2(2m+2)+2(4m-5)=30

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Solution for 2(2m+2)+2(4m-5)=30 equation: 



2(2m+2)+2(4m-5)=30

We move all terms to the left:

2(2m+2)+2(4m-5)-(30)=0

We multiply parentheses

4m+8m+4-10-30=0

We add all the numbers together, and all the variables

12m-36=0

We move all terms containing m to the left, all other terms to the right

12m=36

m=36/12

m=3

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