2(2m+2)+3(3m-5)=28

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Solution for 2(2m+2)+3(3m-5)=28 equation: 



2(2m+2)+3(3m-5)=28

We move all terms to the left:

2(2m+2)+3(3m-5)-(28)=0

We multiply parentheses

4m+9m+4-15-28=0

We add all the numbers together, and all the variables

13m-39=0

We move all terms containing m to the left, all other terms to the right

13m=39

m=39/13

m=3

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