2(2m+2)=-(m-6)+4m

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Solution for 2(2m+2)=-(m-6)+4m equation: 



2(2m+2)=-(m-6)+4m

We move all terms to the left:

2(2m+2)-(-(m-6)+4m)=0

We multiply parentheses

4m-(-(m-6)+4m)+4=0



We calculate terms in parentheses: -(-(m-6)+4m), so:

-(m-6)+4m

We add all the numbers together, and all the variables

4m-(m-6)

We get rid of parentheses

4m-m+6

We add all the numbers together, and all the variables

3m+6

Back to the equation:

-(3m+6)



We get rid of parentheses

4m-3m-6+4=0

We add all the numbers together, and all the variables

m-2=0

We move all terms containing m to the left, all other terms to the right

m=2

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