2(2m+3)=4(m+5)-4

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Solution for 2(2m+3)=4(m+5)-4 equation:


Simplifying
2(2m + 3) = 4(m + 5) + -4

Reorder the terms:
2(3 + 2m) = 4(m + 5) + -4
(3 * 2 + 2m * 2) = 4(m + 5) + -4
(6 + 4m) = 4(m + 5) + -4

Reorder the terms:
6 + 4m = 4(5 + m) + -4
6 + 4m = (5 * 4 + m * 4) + -4
6 + 4m = (20 + 4m) + -4

Reorder the terms:
6 + 4m = 20 + -4 + 4m

Combine like terms: 20 + -4 = 16
6 + 4m = 16 + 4m

Add '-4m' to each side of the equation.
6 + 4m + -4m = 16 + 4m + -4m

Combine like terms: 4m + -4m = 0
6 + 0 = 16 + 4m + -4m
6 = 16 + 4m + -4m

Combine like terms: 4m + -4m = 0
6 = 16 + 0
6 = 16

Solving
6 = 16

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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