2(2m+4)=4(2+m)

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Solution for 2(2m+4)=4(2+m) equation: 



2(2m+4)=4(2+m)

We move all terms to the left:

2(2m+4)-(4(2+m))=0

We add all the numbers together, and all the variables

2(2m+4)-(4(m+2))=0

We multiply parentheses

4m-(4(m+2))+8=0



We calculate terms in parentheses: -(4(m+2)), so:

4(m+2)

We multiply parentheses

4m+8

Back to the equation:

-(4m+8)



We get rid of parentheses

4m-4m-8+8=0

We add all the numbers together, and all the variables

=0

m=0/1

m=0

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