2(2m-1)+5m=3(m-2)+10

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Solution for 2(2m-1)+5m=3(m-2)+10 equation: 



2(2m-1)+5m=3(m-2)+10

We move all terms to the left:

2(2m-1)+5m-(3(m-2)+10)=0

We add all the numbers together, and all the variables

5m+2(2m-1)-(3(m-2)+10)=0

We multiply parentheses

5m+4m-(3(m-2)+10)-2=0



We calculate terms in parentheses: -(3(m-2)+10), so:

3(m-2)+10

We multiply parentheses

3m-6+10

We add all the numbers together, and all the variables

3m+4

Back to the equation:

-(3m+4)



We add all the numbers together, and all the variables

9m-(3m+4)-2=0

We get rid of parentheses

9m-3m-4-2=0

We add all the numbers together, and all the variables

6m-6=0

We move all terms containing m to the left, all other terms to the right

6m=6

m=6/6

m=1

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