2(2n)+2(n+4)=2n+2(4n-10)

Solution for 2(2n)+2(n+4)=2n+2(4n-10) equation:

2(2n)+2(n+4)=2n+2(4n-10)

We move all terms to the left:

2(2n)+2(n+4)-(2n+2(4n-10))=0

We multiply parentheses

22n+2n-(2n+2(4n-10))+8=0


We calculate terms in parentheses: -(2n+2(4n-10)), so:

2n+2(4n-10)

We multiply parentheses

2n+8n-20

We add all the numbers together, and all the variables

10n-20

Back to the equation:

-(10n-20)


We add all the numbers together, and all the variables

24n-(10n-20)+8=0

We get rid of parentheses

24n-10n+20+8=0

We add all the numbers together, and all the variables

14n+28=0

We move all terms containing n to the left, all other terms to the right

14n=-28

n=-28/14

n=-2