2(2n+1)-(n-4)=4(n+5)

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Solution for 2(2n+1)-(n-4)=4(n+5) equation:


Simplifying
2(2n + 1) + -1(n + -4) = 4(n + 5)

Reorder the terms:
2(1 + 2n) + -1(n + -4) = 4(n + 5)
(1 * 2 + 2n * 2) + -1(n + -4) = 4(n + 5)
(2 + 4n) + -1(n + -4) = 4(n + 5)

Reorder the terms:
2 + 4n + -1(-4 + n) = 4(n + 5)
2 + 4n + (-4 * -1 + n * -1) = 4(n + 5)
2 + 4n + (4 + -1n) = 4(n + 5)

Reorder the terms:
2 + 4 + 4n + -1n = 4(n + 5)

Combine like terms: 2 + 4 = 6
6 + 4n + -1n = 4(n + 5)

Combine like terms: 4n + -1n = 3n
6 + 3n = 4(n + 5)

Reorder the terms:
6 + 3n = 4(5 + n)
6 + 3n = (5 * 4 + n * 4)
6 + 3n = (20 + 4n)

Solving
6 + 3n = 20 + 4n

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '-4n' to each side of the equation.
6 + 3n + -4n = 20 + 4n + -4n

Combine like terms: 3n + -4n = -1n
6 + -1n = 20 + 4n + -4n

Combine like terms: 4n + -4n = 0
6 + -1n = 20 + 0
6 + -1n = 20

Add '-6' to each side of the equation.
6 + -6 + -1n = 20 + -6

Combine like terms: 6 + -6 = 0
0 + -1n = 20 + -6
-1n = 20 + -6

Combine like terms: 20 + -6 = 14
-1n = 14

Divide each side by '-1'.
n = -14

Simplifying
n = -14

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