2(2n+1)=7(9n+4)+6

Solution for 2(2n+1)=7(9n+4)+6 equation:

2(2n+1)=7(9n+4)+6

We move all terms to the left:

2(2n+1)-(7(9n+4)+6)=0

We multiply parentheses

4n-(7(9n+4)+6)+2=0


We calculate terms in parentheses: -(7(9n+4)+6), so:

7(9n+4)+6

We multiply parentheses

63n+28+6

We add all the numbers together, and all the variables

63n+34

Back to the equation:

-(63n+34)


We get rid of parentheses

4n-63n-34+2=0

We add all the numbers together, and all the variables

-59n-32=0

We move all terms containing n to the left, all other terms to the right

-59n=32

n=32/-59

n=-32/59