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2(2n+2)+1=10+2n-5
We move all terms to the left:
2(2n+2)+1-(10+2n-5)=0
We add all the numbers together, and all the variables
2(2n+2)-(2n+5)+1=0
We multiply parentheses
4n-(2n+5)+4+1=0
We get rid of parentheses
4n-2n-5+4+1=0
We add all the numbers together, and all the variables
2n=0
n=0/2
n=0
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