2(2n-2)=3(n+5)

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Solution for 2(2n-2)=3(n+5) equation: 



2(2n-2)=3(n+5)

We move all terms to the left:

2(2n-2)-(3(n+5))=0

We multiply parentheses

4n-(3(n+5))-4=0



We calculate terms in parentheses: -(3(n+5)), so:

3(n+5)

We multiply parentheses

3n+15

Back to the equation:

-(3n+15)



We get rid of parentheses

4n-3n-15-4=0

We add all the numbers together, and all the variables

n-19=0

We move all terms containing n to the left, all other terms to the right

n=19

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