2(2n-3)=3(n+2)

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Solution for 2(2n-3)=3(n+2) equation: 



2(2n-3)=3(n+2)

We move all terms to the left:

2(2n-3)-(3(n+2))=0

We multiply parentheses

4n-(3(n+2))-6=0



We calculate terms in parentheses: -(3(n+2)), so:

3(n+2)

We multiply parentheses

3n+6

Back to the equation:

-(3n+6)



We get rid of parentheses

4n-3n-6-6=0

We add all the numbers together, and all the variables

n-12=0

We move all terms containing n to the left, all other terms to the right

n=12

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