2(2p+2)=3(p-4)

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Solution for 2(2p+2)=3(p-4) equation: 



2(2p+2)=3(p-4)

We move all terms to the left:

2(2p+2)-(3(p-4))=0

We multiply parentheses

4p-(3(p-4))+4=0



We calculate terms in parentheses: -(3(p-4)), so:

3(p-4)

We multiply parentheses

3p-12

Back to the equation:

-(3p-12)



We get rid of parentheses

4p-3p+12+4=0

We add all the numbers together, and all the variables

p+16=0

We move all terms containing p to the left, all other terms to the right

p=-16

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