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2(2p-3)=3(p+2)
We move all terms to the left:
2(2p-3)-(3(p+2))=0
We multiply parentheses
4p-(3(p+2))-6=0
We calculate terms in parentheses: -(3(p+2)), so:We get rid of parentheses
3(p+2)
We multiply parentheses
3p+6
Back to the equation:
-(3p+6)
4p-3p-6-6=0
We add all the numbers together, and all the variables
p-12=0
We move all terms containing p to the left, all other terms to the right
p=12
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