2(2r+1)=3(r-4)

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Solution for 2(2r+1)=3(r-4) equation: 



2(2r+1)=3(r-4)

We move all terms to the left:

2(2r+1)-(3(r-4))=0

We multiply parentheses

4r-(3(r-4))+2=0



We calculate terms in parentheses: -(3(r-4)), so:

3(r-4)

We multiply parentheses

3r-12

Back to the equation:

-(3r-12)



We get rid of parentheses

4r-3r+12+2=0

We add all the numbers together, and all the variables

r+14=0

We move all terms containing r to the left, all other terms to the right

r=-14

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