2(2r+3)=r+18

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Solution for 2(2r+3)=r+18 equation: 



2(2r+3)=r+18

We move all terms to the left:

2(2r+3)-(r+18)=0

We multiply parentheses

4r-(r+18)+6=0

We get rid of parentheses

4r-r-18+6=0

We add all the numbers together, and all the variables

3r-12=0

We move all terms containing r to the left, all other terms to the right

3r=12

r=12/3

r=4

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