2(2r+4)=2/3(24-8r)

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Solution for 2(2r+4)=2/3(24-8r) equation: 



2(2r+4)=2/3(24-8r)

We move all terms to the left:

2(2r+4)-(2/3(24-8r))=0



Domain of the equation: 3(24-8r))!=0

r∈R



We add all the numbers together, and all the variables

2(2r+4)-(2/3(-8r+24))=0

We multiply parentheses

4r-(2/3(-8r+24))+8=0

We multiply all the terms by the denominator


4r*3(-8r+24))-(2+8*3(-8r+24))=0

Wy multiply elements

12r^2(-+24r(-=0

We use the square of the difference formula

12r^2(-24r(-=0

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