2(2s-5)+1=2(s+4)-1

Solution for 2(2s-5)+1=2(s+4)-1 equation:

2(2s-5)+1=2(s+4)-1

We move all terms to the left:

2(2s-5)+1-(2(s+4)-1)=0

We multiply parentheses

4s-(2(s+4)-1)-10+1=0


We calculate terms in parentheses: -(2(s+4)-1), so:

2(s+4)-1

We multiply parentheses

2s+8-1

We add all the numbers together, and all the variables

2s+7

Back to the equation:

-(2s+7)


We add all the numbers together, and all the variables

4s-(2s+7)-9=0

We get rid of parentheses

4s-2s-7-9=0

We add all the numbers together, and all the variables

2s-16=0

We move all terms containing s to the left, all other terms to the right

2s=16

s=16/2

s=8