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2(2t+)=3/4(24-8t)
We move all terms to the left:
2(2t+)-(3/4(24-8t))=0
Domain of the equation: 4(24-8t))!=0We add all the numbers together, and all the variables
t∈R
2(+2t)-(3/4(-8t+24))=0
We multiply parentheses
4t-(3/4(-8t+24))=0
We multiply all the terms by the denominator
4t*4(-8t+24))-(3=0
Wy multiply elements
16t^2(-=0
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