2(2t+-3)=6(1+2)

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Solution for 2(2t+-3)=6(1+2) equation: 



2(2t+-3)=6(1+2)

We move all terms to the left:

2(2t+-3)-(6(1+2))=0

We add all the numbers together, and all the variables

2(2t-3)-(63)=0

We add all the numbers together, and all the variables

2(2t-3)-63=0

We multiply parentheses

4t-6-63=0

We add all the numbers together, and all the variables

4t-69=0

We move all terms containing t to the left, all other terms to the right

4t=69

t=69/4

t=17+1/4

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