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2(2t+2)=3/4(24-8t)
We move all terms to the left:
2(2t+2)-(3/4(24-8t))=0
Domain of the equation: 4(24-8t))!=0We add all the numbers together, and all the variables
t∈R
2(2t+2)-(3/4(-8t+24))=0
We multiply parentheses
4t-(3/4(-8t+24))+4=0
We multiply all the terms by the denominator
4t*4(-8t+24))-(3+4*4(-8t+24))=0
Wy multiply elements
16t^2(-+16t(-=0
We use the square of the difference formula
16t^2(-16t(-=0
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