2(2t+4)=19+6t

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Solution for 2(2t+4)=19+6t equation: 



2(2t+4)=19+6t

We move all terms to the left:

2(2t+4)-(19+6t)=0

We add all the numbers together, and all the variables

2(2t+4)-(6t+19)=0

We multiply parentheses

4t-(6t+19)+8=0

We get rid of parentheses

4t-6t-19+8=0

We add all the numbers together, and all the variables

-2t-11=0

We move all terms containing t to the left, all other terms to the right

-2t=11

t=11/-2

t=-5+1/2

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