2(2t+4)=3-3/4(24-8t)

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Solution for 2(2t+4)=3-3/4(24-8t) equation: 



2(2t+4)=3-3/4(24-8t)

We move all terms to the left:

2(2t+4)-(3-3/4(24-8t))=0



Domain of the equation: 4(24-8t))!=0

t∈R



We add all the numbers together, and all the variables

2(2t+4)-(3-3/4(-8t+24))=0

We multiply parentheses

4t-(3-3/4(-8t+24))+8=0

We multiply all the terms by the denominator


4t*4(-8t+24))-(3+8*4(-8t+24))-3=0

Wy multiply elements

16t^2(-+32t(-=0

We use the square of the difference formula

16t^2(-32t(-=0

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