2(2t+4)=3/4(24-18t)

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Solution for 2(2t+4)=3/4(24-18t) equation:



2(2t+4)=3/4(24-18t)
We move all terms to the left:
2(2t+4)-(3/4(24-18t))=0
Domain of the equation: 4(24-18t))!=0
t∈R
We add all the numbers together, and all the variables
2(2t+4)-(3/4(-18t+24))=0
We multiply parentheses
4t-(3/4(-18t+24))+8=0
We multiply all the terms by the denominator
4t*4(-18t+24))-(3+8*4(-18t+24))=0
Wy multiply elements
16t^2(-+32t(-=0
We use the square of the difference formula
16t^2(-32t(-=0

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