2(2t+4)=3/4(28-8t)

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Solution for 2(2t+4)=3/4(28-8t) equation: 



2(2t+4)=3/4(28-8t)

We move all terms to the left:

2(2t+4)-(3/4(28-8t))=0



Domain of the equation: 4(28-8t))!=0

t∈R



We add all the numbers together, and all the variables

2(2t+4)-(3/4(-8t+28))=0

We multiply parentheses

4t-(3/4(-8t+28))+8=0

We multiply all the terms by the denominator


4t*4(-8t+28))-(3+8*4(-8t+28))=0

Wy multiply elements

16t^2(-+32t(-=0

We use the square of the difference formula

16t^2(-32t(-=0

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