2(2t-1)+15=5(t-2)-(2t+3)

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Solution for 2(2t-1)+15=5(t-2)-(2t+3) equation: 



2(2t-1)+15=5(t-2)-(2t+3)

We move all terms to the left:

2(2t-1)+15-(5(t-2)-(2t+3))=0

We multiply parentheses

4t-(5(t-2)-(2t+3))-2+15=0



We calculate terms in parentheses: -(5(t-2)-(2t+3)), so:

5(t-2)-(2t+3)

We multiply parentheses

5t-(2t+3)-10

We get rid of parentheses

5t-2t-3-10

We add all the numbers together, and all the variables

3t-13

Back to the equation:

-(3t-13)



We add all the numbers together, and all the variables

4t-(3t-13)+13=0

We get rid of parentheses

4t-3t+13+13=0

We add all the numbers together, and all the variables

t+26=0

We move all terms containing t to the left, all other terms to the right

t=-26

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