2(2t-1)-4=t-(t-1)

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Solution for 2(2t-1)-4=t-(t-1) equation: 



2(2t-1)-4=t-(t-1)

We move all terms to the left:

2(2t-1)-4-(t-(t-1))=0

We multiply parentheses

4t-(t-(t-1))-2-4=0



We calculate terms in parentheses: -(t-(t-1)), so:

t-(t-1)

We get rid of parentheses

t-t+1

We add all the numbers together, and all the variables

1

Back to the equation:

-(1)



We add all the numbers together, and all the variables

4t-7=0

We move all terms containing t to the left, all other terms to the right

4t=7

t=7/4

t=1+3/4

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