2(2t-2)=4-2t

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Solution for 2(2t-2)=4-2t equation: 



2(2t-2)=4-2t

We move all terms to the left:

2(2t-2)-(4-2t)=0

We add all the numbers together, and all the variables

2(2t-2)-(-2t+4)=0

We multiply parentheses

4t-(-2t+4)-4=0

We get rid of parentheses

4t+2t-4-4=0

We add all the numbers together, and all the variables

6t-8=0

We move all terms containing t to the left, all other terms to the right

6t=8

t=8/6

t=1+1/3

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