2(2t-3)=6(t*2)

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Solution for 2(2t-3)=6(t*2) equation:



2(2t-3)=6(t*2)
We move all terms to the left:
2(2t-3)-(6(t*2))=0
We add all the numbers together, and all the variables
2(2t-3)-(6(+t*2))=0
We multiply parentheses
4t-(6(+t*2))-6=0
We calculate terms in parentheses: -(6(+t*2)), so:
6(+t*2)
We multiply parentheses
12t
Back to the equation:
-(12t)
We add all the numbers together, and all the variables
-8t-6=0
We move all terms containing t to the left, all other terms to the right
-8t=6
t=6/-8
t=-3/4

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