2(2t-3)=6(t*2)

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Solution for 2(2t-3)=6(t*2) equation: 



2(2t-3)=6(t*2)

We move all terms to the left:

2(2t-3)-(6(t*2))=0

We add all the numbers together, and all the variables

2(2t-3)-(6(+t*2))=0

We multiply parentheses

4t-(6(+t*2))-6=0



We calculate terms in parentheses: -(6(+t*2)), so:

6(+t*2)

We multiply parentheses

12t

Back to the equation:

-(12t)



We add all the numbers together, and all the variables

-8t-6=0

We move all terms containing t to the left, all other terms to the right

-8t=6

t=6/-8

t=-3/4

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