2(2u-3)=3(u+5)

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Solution for 2(2u-3)=3(u+5) equation: 



2(2u-3)=3(u+5)

We move all terms to the left:

2(2u-3)-(3(u+5))=0

We multiply parentheses

4u-(3(u+5))-6=0



We calculate terms in parentheses: -(3(u+5)), so:

3(u+5)

We multiply parentheses

3u+15

Back to the equation:

-(3u+15)



We get rid of parentheses

4u-3u-15-6=0

We add all the numbers together, and all the variables

u-21=0

We move all terms containing u to the left, all other terms to the right

u=21

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