2(2v+1)+7v=6(v+4)+3v

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Solution for 2(2v+1)+7v=6(v+4)+3v equation:


Simplifying
2(2v + 1) + 7v = 6(v + 4) + 3v

Reorder the terms:
2(1 + 2v) + 7v = 6(v + 4) + 3v
(1 * 2 + 2v * 2) + 7v = 6(v + 4) + 3v
(2 + 4v) + 7v = 6(v + 4) + 3v

Combine like terms: 4v + 7v = 11v
2 + 11v = 6(v + 4) + 3v

Reorder the terms:
2 + 11v = 6(4 + v) + 3v
2 + 11v = (4 * 6 + v * 6) + 3v
2 + 11v = (24 + 6v) + 3v

Combine like terms: 6v + 3v = 9v
2 + 11v = 24 + 9v

Solving
2 + 11v = 24 + 9v

Solving for variable 'v'.

Move all terms containing v to the left, all other terms to the right.

Add '-9v' to each side of the equation.
2 + 11v + -9v = 24 + 9v + -9v

Combine like terms: 11v + -9v = 2v
2 + 2v = 24 + 9v + -9v

Combine like terms: 9v + -9v = 0
2 + 2v = 24 + 0
2 + 2v = 24

Add '-2' to each side of the equation.
2 + -2 + 2v = 24 + -2

Combine like terms: 2 + -2 = 0
0 + 2v = 24 + -2
2v = 24 + -2

Combine like terms: 24 + -2 = 22
2v = 22

Divide each side by '2'.
v = 11

Simplifying
v = 11

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