2(2v+3)+7v+8=6(v+1)-3v

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Solution for 2(2v+3)+7v+8=6(v+1)-3v equation: 



2(2v+3)+7v+8=6(v+1)-3v

We move all terms to the left:

2(2v+3)+7v+8-(6(v+1)-3v)=0

We add all the numbers together, and all the variables

7v+2(2v+3)-(6(v+1)-3v)+8=0

We multiply parentheses

7v+4v-(6(v+1)-3v)+6+8=0



We calculate terms in parentheses: -(6(v+1)-3v), so:

6(v+1)-3v

We add all the numbers together, and all the variables

-3v+6(v+1)

We multiply parentheses

-3v+6v+6

We add all the numbers together, and all the variables

3v+6

Back to the equation:

-(3v+6)



We add all the numbers together, and all the variables

11v-(3v+6)+14=0

We get rid of parentheses

11v-3v-6+14=0

We add all the numbers together, and all the variables

8v+8=0

We move all terms containing v to the left, all other terms to the right

8v=-8

v=-8/8

v=-1

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