2(2v+3)+8=6(v-1)+3v

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Solution for 2(2v+3)+8=6(v-1)+3v equation: 



2(2v+3)+8=6(v-1)+3v

We move all terms to the left:

2(2v+3)+8-(6(v-1)+3v)=0

We multiply parentheses

4v-(6(v-1)+3v)+6+8=0



We calculate terms in parentheses: -(6(v-1)+3v), so:

6(v-1)+3v

We add all the numbers together, and all the variables

3v+6(v-1)

We multiply parentheses

3v+6v-6

We add all the numbers together, and all the variables

9v-6

Back to the equation:

-(9v-6)



We add all the numbers together, and all the variables

4v-(9v-6)+14=0

We get rid of parentheses

4v-9v+6+14=0

We add all the numbers together, and all the variables

-5v+20=0

We move all terms containing v to the left, all other terms to the right

-5v=-20

v=-20/-5

v=+4

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