2(2x)+2(3x-12)=76

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Solution for 2(2x)+2(3x-12)=76 equation: 



2(2x)+2(3x-12)=76

We move all terms to the left:

2(2x)+2(3x-12)-(76)=0

We multiply parentheses

22x+6x-24-76=0

We add all the numbers together, and all the variables

28x-100=0

We move all terms containing x to the left, all other terms to the right

28x=100

x=100/28

x=3+4/7

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