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2(2x+-5)=3(x-6)
We move all terms to the left:
2(2x+-5)-(3(x-6))=0
We add all the numbers together, and all the variables
2(2x-5)-(3(x-6))=0
We multiply parentheses
4x-(3(x-6))-10=0
We calculate terms in parentheses: -(3(x-6)), so:We get rid of parentheses
3(x-6)
We multiply parentheses
3x-18
Back to the equation:
-(3x-18)
4x-3x+18-10=0
We add all the numbers together, and all the variables
x+8=0
We move all terms containing x to the left, all other terms to the right
x=-8
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