2(2x+1)+2(3x+3)=78

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Solution for 2(2x+1)+2(3x+3)=78 equation:


Simplifying
2(2x + 1) + 2(3x + 3) = 78

Reorder the terms:
2(1 + 2x) + 2(3x + 3) = 78
(1 * 2 + 2x * 2) + 2(3x + 3) = 78
(2 + 4x) + 2(3x + 3) = 78

Reorder the terms:
2 + 4x + 2(3 + 3x) = 78
2 + 4x + (3 * 2 + 3x * 2) = 78
2 + 4x + (6 + 6x) = 78

Reorder the terms:
2 + 6 + 4x + 6x = 78

Combine like terms: 2 + 6 = 8
8 + 4x + 6x = 78

Combine like terms: 4x + 6x = 10x
8 + 10x = 78

Solving
8 + 10x = 78

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-8' to each side of the equation.
8 + -8 + 10x = 78 + -8

Combine like terms: 8 + -8 = 0
0 + 10x = 78 + -8
10x = 78 + -8

Combine like terms: 78 + -8 = 70
10x = 70

Divide each side by '10'.
x = 7

Simplifying
x = 7

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