2(2x+1)+3(4x-2)=36

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Solution for 2(2x+1)+3(4x-2)=36 equation: 



2(2x+1)+3(4x-2)=36

We move all terms to the left:

2(2x+1)+3(4x-2)-(36)=0

We multiply parentheses

4x+12x+2-6-36=0

We add all the numbers together, and all the variables

16x-40=0

We move all terms containing x to the left, all other terms to the right

16x=40

x=40/16

x=2+1/2

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