2(2x+1)+x=4(x-1)+7

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Solution for 2(2x+1)+x=4(x-1)+7 equation: 



2(2x+1)+x=4(x-1)+7

We move all terms to the left:

2(2x+1)+x-(4(x-1)+7)=0

We add all the numbers together, and all the variables

x+2(2x+1)-(4(x-1)+7)=0

We multiply parentheses

x+4x-(4(x-1)+7)+2=0



We calculate terms in parentheses: -(4(x-1)+7), so:

4(x-1)+7

We multiply parentheses

4x-4+7

We add all the numbers together, and all the variables

4x+3

Back to the equation:

-(4x+3)



We add all the numbers together, and all the variables

5x-(4x+3)+2=0

We get rid of parentheses

5x-4x-3+2=0

We add all the numbers together, and all the variables

x-1=0

We move all terms containing x to the left, all other terms to the right

x=1

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