2(2x+1)-(x+3)=3x-4(2-x)

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Solution for 2(2x+1)-(x+3)=3x-4(2-x) equation: 



2(2x+1)-(x+3)=3x-4(2-x)

We move all terms to the left:

2(2x+1)-(x+3)-(3x-4(2-x))=0

We add all the numbers together, and all the variables

2(2x+1)-(x+3)-(3x-4(-1x+2))=0

We multiply parentheses

4x-(x+3)-(3x-4(-1x+2))+2=0

We get rid of parentheses

4x-x-(3x-4(-1x+2))-3+2=0



We calculate terms in parentheses: -(3x-4(-1x+2)), so:

3x-4(-1x+2)

We multiply parentheses

3x+4x-8

We add all the numbers together, and all the variables

7x-8

Back to the equation:

-(7x-8)



We add all the numbers together, and all the variables

3x-(7x-8)-1=0

We get rid of parentheses

3x-7x+8-1=0

We add all the numbers together, and all the variables

-4x+7=0

We move all terms containing x to the left, all other terms to the right

-4x=-7

x=-7/-4

x=1+3/4

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