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2(2x+1)-1=3(x+4)
We move all terms to the left:
2(2x+1)-1-(3(x+4))=0
We multiply parentheses
4x-(3(x+4))+2-1=0
We calculate terms in parentheses: -(3(x+4)), so:We add all the numbers together, and all the variables
3(x+4)
We multiply parentheses
3x+12
Back to the equation:
-(3x+12)
4x-(3x+12)+1=0
We get rid of parentheses
4x-3x-12+1=0
We add all the numbers together, and all the variables
x-11=0
We move all terms containing x to the left, all other terms to the right
x=11
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