2(2x+1)=0.5x(2x-14)

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Solution for 2(2x+1)=0.5x(2x-14) equation:



2(2x+1)=0.5x(2x-14)
We move all terms to the left:
2(2x+1)-(0.5x(2x-14))=0
We multiply parentheses
4x-(0.5x(2x-14))+2=0
We calculate terms in parentheses: -(0.5x(2x-14)), so:
0.5x(2x-14)
We multiply parentheses
0x^2+0x
We add all the numbers together, and all the variables
x^2+x
Back to the equation:
-(x^2+x)
We get rid of parentheses
-x^2+4x-x+2=0
We add all the numbers together, and all the variables
-1x^2+3x+2=0
a = -1; b = 3; c = +2;
Δ = b2-4ac
Δ = 32-4·(-1)·2
Δ = 17
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{17}}{2*-1}=\frac{-3-\sqrt{17}}{-2} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{17}}{2*-1}=\frac{-3+\sqrt{17}}{-2} $

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