2(2x+1)=102-5(3x+1)

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Solution for 2(2x+1)=102-5(3x+1) equation: 



2(2x+1)=102-5(3x+1)

We move all terms to the left:

2(2x+1)-(102-5(3x+1))=0

We multiply parentheses

4x-(102-5(3x+1))+2=0



We calculate terms in parentheses: -(102-5(3x+1)), so:

102-5(3x+1)

determiningTheFunctionDomain
-5(3x+1)+102

We multiply parentheses

-15x-5+102

We add all the numbers together, and all the variables

-15x+97

Back to the equation:

-(-15x+97)



We get rid of parentheses

4x+15x-97+2=0

We add all the numbers together, and all the variables

19x-95=0

We move all terms containing x to the left, all other terms to the right

19x=95

x=95/19

x=5

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