2(2x+2)+4(3-x)=16-2x

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Solution for 2(2x+2)+4(3-x)=16-2x equation: 



2(2x+2)+4(3-x)=16-2x

We move all terms to the left:

2(2x+2)+4(3-x)-(16-2x)=0

We add all the numbers together, and all the variables

2(2x+2)+4(-1x+3)-(-2x+16)=0

We multiply parentheses

4x-4x-(-2x+16)+4+12=0

We get rid of parentheses

4x-4x+2x-16+4+12=0

We add all the numbers together, and all the variables

2x=0

x=0/2

x=0

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