2(2x+3)+10x=41

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Solution for 2(2x+3)+10x=41 equation: 



2(2x+3)+10x=41

We move all terms to the left:

2(2x+3)+10x-(41)=0

We add all the numbers together, and all the variables

10x+2(2x+3)-41=0

We multiply parentheses

10x+4x+6-41=0

We add all the numbers together, and all the variables

14x-35=0

We move all terms containing x to the left, all other terms to the right

14x=35

x=35/14

x=2+1/2

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