2(2x+3)-3x=8-2(2x-5)

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Solution for 2(2x+3)-3x=8-2(2x-5) equation: 



2(2x+3)-3x=8-2(2x-5)

We move all terms to the left:

2(2x+3)-3x-(8-2(2x-5))=0

We add all the numbers together, and all the variables

-3x+2(2x+3)-(8-2(2x-5))=0

We multiply parentheses

-3x+4x-(8-2(2x-5))+6=0



We calculate terms in parentheses: -(8-2(2x-5)), so:

8-2(2x-5)

determiningTheFunctionDomain
-2(2x-5)+8

We multiply parentheses

-4x+10+8

We add all the numbers together, and all the variables

-4x+18

Back to the equation:

-(-4x+18)



We add all the numbers together, and all the variables

x-(-4x+18)+6=0

We get rid of parentheses

x+4x-18+6=0

We add all the numbers together, and all the variables

5x-12=0

We move all terms containing x to the left, all other terms to the right

5x=12

x=12/5

x=2+2/5

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