2(2x+3)-7=18-5(x+4)

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Solution for 2(2x+3)-7=18-5(x+4) equation: 



2(2x+3)-7=18-5(x+4)

We move all terms to the left:

2(2x+3)-7-(18-5(x+4))=0

We multiply parentheses

4x-(18-5(x+4))+6-7=0



We calculate terms in parentheses: -(18-5(x+4)), so:

18-5(x+4)

determiningTheFunctionDomain
-5(x+4)+18

We multiply parentheses

-5x-20+18

We add all the numbers together, and all the variables

-5x-2

Back to the equation:

-(-5x-2)



We add all the numbers together, and all the variables

4x-(-5x-2)-1=0

We get rid of parentheses

4x+5x+2-1=0

We add all the numbers together, and all the variables

9x+1=0

We move all terms containing x to the left, all other terms to the right

9x=-1

x=-1/9

x=-1/9

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