2(2x+3)-7x=18+6(x+2x)

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Solution for 2(2x+3)-7x=18+6(x+2x) equation: 



2(2x+3)-7x=18+6(x+2x)

We move all terms to the left:

2(2x+3)-7x-(18+6(x+2x))=0

We add all the numbers together, and all the variables

2(2x+3)-7x-(18+6(+3x))=0

We add all the numbers together, and all the variables

-7x+2(2x+3)-(18+6(+3x))=0

We multiply parentheses

-7x+4x-(18+6(+3x))+6=0



We calculate terms in parentheses: -(18+6(+3x)), so:

18+6(+3x)

determiningTheFunctionDomain
6(+3x)+18

We multiply parentheses

18x+18

Back to the equation:

-(18x+18)



We add all the numbers together, and all the variables

-3x-(18x+18)+6=0

We get rid of parentheses

-3x-18x-18+6=0

We add all the numbers together, and all the variables

-21x-12=0

We move all terms containing x to the left, all other terms to the right

-21x=12

x=12/-21

x=-4/7

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