2(2x+3)-7x=18-5(x+2x)

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Solution for 2(2x+3)-7x=18-5(x+2x) equation: 



2(2x+3)-7x=18-5(x+2x)

We move all terms to the left:

2(2x+3)-7x-(18-5(x+2x))=0

We add all the numbers together, and all the variables

2(2x+3)-7x-(18-5(+3x))=0

We add all the numbers together, and all the variables

-7x+2(2x+3)-(18-5(+3x))=0

We multiply parentheses

-7x+4x-(18-5(+3x))+6=0



We calculate terms in parentheses: -(18-5(+3x)), so:

18-5(+3x)

determiningTheFunctionDomain
-5(+3x)+18

We multiply parentheses

-15x+18

Back to the equation:

-(-15x+18)



We add all the numbers together, and all the variables

-3x-(-15x+18)+6=0

We get rid of parentheses

-3x+15x-18+6=0

We add all the numbers together, and all the variables

12x-12=0

We move all terms containing x to the left, all other terms to the right

12x=12

x=12/12

x=1

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