2(2x+3)-7x=23-(x+3x)

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Solution for 2(2x+3)-7x=23-(x+3x) equation: 



2(2x+3)-7x=23-(x+3x)

We move all terms to the left:

2(2x+3)-7x-(23-(x+3x))=0

We add all the numbers together, and all the variables

2(2x+3)-7x-(23-(+4x))=0

We add all the numbers together, and all the variables

-7x+2(2x+3)-(23-(+4x))=0

We multiply parentheses

-7x+4x-(23-(+4x))+6=0



We calculate terms in parentheses: -(23-(+4x)), so:

23-(+4x)

determiningTheFunctionDomain
-(+4x)+23

We get rid of parentheses

-4x+23

Back to the equation:

-(-4x+23)



We add all the numbers together, and all the variables

-3x-(-4x+23)+6=0

We get rid of parentheses

-3x+4x-23+6=0

We add all the numbers together, and all the variables

x-17=0

We move all terms containing x to the left, all other terms to the right

x=17

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