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2(2x+3)=3(x+2)
We move all terms to the left:
2(2x+3)-(3(x+2))=0
We multiply parentheses
4x-(3(x+2))+6=0
We calculate terms in parentheses: -(3(x+2)), so:We get rid of parentheses
3(x+2)
We multiply parentheses
3x+6
Back to the equation:
-(3x+6)
4x-3x-6+6=0
We add all the numbers together, and all the variables
x=0
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